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28x^2=700
We move all terms to the left:
28x^2-(700)=0
a = 28; b = 0; c = -700;
Δ = b2-4ac
Δ = 02-4·28·(-700)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{78400}=280$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-280}{2*28}=\frac{-280}{56} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+280}{2*28}=\frac{280}{56} =5 $
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